‌ When ‌2.46‌ g of ‌‌ a ‌‌ hydrated salt ‌(MSO4xH2O)‌‌ is completely ‌‌ dehydrated, 1.20g of anhydrous salt is obtained. If the molecular weight of anhydrous saltis 120gmol−1, what is the value of x?
Molecular weight of MSO4=120g∕mol Molecular wergnt ot MSO4⋅xH2O =120g+x×18g (120g+x.18g) of MSO4⋅x+↓2O on complete dehydration gives 120g of MSO4lg gives =‌