KEAM 2016 Math Paper

Given, 5 positive and 6 negative numbers.
∴ Total numbers =5+6=11
Three numbers are chosen at random and multiplied.
∴ Favourable number of cases
=‌5C2⋅‌6C1+‌6C3
=10⋅6+20=60+20=80
Total number of cases =‌11C3
=‌

11!

3!8!

=‌

11×10×9

6

=165
Hence, the required probability