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Question : 70 of 120
Marks:
+1,
-0
Solution:
Given,
a×b+b×c+c×a =λ(a×b) .....(i)
and
a+2b−c=0 Let
a=,b= ⇒‌‌c=+2 Substituting the values in Eq. (i)
⇒‌‌()+(−)+(−2)=λ() ⇒‌‌−2=λ ⇒‌‌λ=−2
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