KEAM 2016 Math Paper

Given equation is
ax2−bx+a=0.....(i)
and one root is 6 .
Let α and β are the roots of the equation andα=6. From the equation
From the equation
α+β=‌

b

a

⇒‌‌6+β=‌

b

a

.....(ii)
and αβ=‌

a

a

=1⇒β=‌

1

α

=‌

1

6

By putting β=‌

1

6

in Eq. (ii), we get
6+‌

1

6

=‌

b

a

⇒‌

b

a

=‌

37

6