KEAM 2016 Math Paper

We have, y2=16−x2
⇒‌‌x2+y2=16 ....(i)
Eq, (i) is equation of circle with radius 4.
Required area =

4

∫

0

√16−x2dx
Alternate method Now, area of the region bounded by y2=16−x2,y=0 and x=0 in the first quadrant is a quadrant of circle∴‌‌A=‌

1

4

πr2=‌

1

4

π×42=4πsq units