KEAM 2016 Math Paper

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Question : 101 of 120

Marks: +1, -0

The equation of the tangent to the curve y=x3–6x+5 at (2,1) is

6x – y – 11 = 0
6x – y – 13 = 0
6x + y + 11 = 0
6x – y + 11 = 0
x – 6y – 11 = 0

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