KEAM 2015 Physics and Chemistry Paper

Let in the first case, the total energy at the throwing point be 5E.
KE at a particular height =3E. potential energy at the height =2E
As velocity of throw is doubled, kinetic energy becomes 4 times.
∴ Total KE at the throwing point 20E
PE at the same height =2E (will remain same as the previous value) and KE at the same height =18E
‌

PE

KE

=‌

2E

18E

=‌

1

9

=1:9