KEAM 2015 Physics and Chemistry Paper

Given, velocity of bus =10ms−1
Distance between bus and scootorist =1.2km
=1200m
Let the velocity of scootorist be vs
Time =1‌min=60s
Relative velocity of scootorist w.r.t. bus
=(vs−10)ms−1
We know that, time =‌

‌ distance ‌

‌ relative velocity ‌

⇒‌‌60=‌

1200

vs−10

⇒60(vs−10)=1200
⇒60vs−600=1200
⇒60vs=1200+600
⇒60vs=1800
Velocity of a scootorist,
∴‌‌vs=‌

1800

60

=30ms−1