KEAM 2015 Math Paper

Let the slope of the line be m.
Slope of the line 2x+8y=10 is
‌

−2

8

=−‌

1

4

since, both the lines are perpendicular.
∴‌‌m=‌

−1

(−‌ 1 4 )

=4
Hence, equation of the required line will be y=4x+c
It is given that, above line pass through (5,0) .
Then, 0=4×5+c
⇒‌‌c=−20
So, the line will intersect the Y -axis at (0,-20) .