KEAM 2015 Math Paper

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Question : 108 of 120

Marks: +1, -0

lim

x→0

(

10

9

sin 9x

sin 10x

)(

8

7

sin 7x

sin 8x

)(

6

5

sin 5x

sin 6x

)(

4

3

sin 3x

sin 4x

)(

sin x

sin 2x

)=

63
256
1
6
6
5
1
2
256
63

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