KEAM 2014 Math Paper

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Question : 99 of 120

Marks: +1, -0

Let sn=cos(

nπ

10

),n=1,2,3,... Then the value of

s1s2...s10

s1+s2...s10

is equal to

1
√2
√3
2
2√2
0
1
2

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