KEAM 2014 Math Paper

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Question : 84 of 120

Marks: +1, -0

If a1,a2,a3,... are in A.P., then the value of |

a1	a2	1
a2	a3	1
a3	a4	1

| is equal to

a4−a1
a1+a4
2
1
a2+a3
2
0

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