KEAM 2014 Math Paper

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Question : 44 of 120

Marks: +1, -0

∫

√x2−1

x

‌dx is equal to

√x2−1−sec−1x+C
√x2−1+tan−1x+C
√x2−1+sec−1x+C
√x2−1−tan−1x+C
√x2−1+sec x+C

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