The length of the transverse axis of a hyperbola is 2\cos \alpha .The foci of the hyperbola are the same as that of the ellipse 9x^2+16y^2=144. The equation of the hyperbola is

Correct Answer is : x2cos2α−y27−cos2α=1

x^2/{\cos^2\alpha}-y^2/{7-\cos^2\alpha}=1

x^2/{\cos^2\alpha}-y^2/{7+\cos^2\alpha}=1

x^2/{1+\cos^2\alpha}-y^2/{7-\cos^2\alpha}=1

x^2/{1+\cos^2\alpha}-y^2/{7+\cos^2\alpha}=1

x^2/{\cos^2\alpha}-y^2/{5-\cos^2\alpha}=1

KEAM 2014 Math Paper

Question : 120 of 120

Marks: +1, -0

The length of the transverse axis of a hyperbola is 2‌cos‌α.The foci of the hyperbola are the same as that of the ellipse 9x2+16y2=144. The equation of the hyperbola is

x2
cos2α
−
y2
7−cos2α
=1
x2
cos2α
−
y2
7+cos2α
=1
x2
1+cos2α
−
y2
7−cos2α
=1
x2
1+cos2α
−
y2
7+cos2α
=1
x2
cos2α
−
y2
5−cos2α
=1

Validate

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