A unit vector parallel to the straight line {x-2}/3=\frac{3+y}{-1}=\frac{z-2}{-4} is

Correct Answer is : 1√26(3⋀i−⋀j−4⋀k)

1/\sqrt{26}(3i^{⋀}-j^{⋀}+4k^{⋀})

1/\sqrt{26}(i^{⋀}+3j^{⋀}-k^{⋀})

1/\sqrt{26}(3i^{⋀}-j^{⋀}-4k^{⋀})

1/\sqrt{26}(3i^{⋀}+j^{⋀}+4k^{⋀})

1/\sqrt{26}(i^{⋀}-3j^{⋀}-k^{⋀})

KEAM 2014 Math Paper

Question : 12 of 120

Marks: +1, -0

A unit vector parallel to the straight line

x−2

3+y

−1

z−2

−4

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