=(r1) (say).....(i) So, (2r1−1,1−3r1,−2r1−1) be any point on line (1) and
x−3
1
=
y−λ
2
=
z
3
=r2 (say) ......(ii) So, (r2+3,2r2+λ,3r2) be any point on line (ii). since, both lines intersect each other. ∴2r1−1=r2+3 ⇒2r1−r2=4.......(iii) −3r1+1=2r2+λ ⇒−3r1−2r2=λ−1.....(iv) and −2r1−1=3r2 ⇒2r1+3r2=−1.....(v) On subtracting Eq. (v) from Eq. (iii), we get −4r2=5⇒r2=−5/4 From Eq. (iii), we get 2r1=4−
5
4
=
11
4
⇒r1=
11
8
On putting the value of r1 and r2 in Eq. (iv), we get −3(