KEAM 2013 Math Paper

Equation of straight line with slope 3 and passing through the point (30,40) is
(y−40)=3(x−30)
⇒‌‌y−40=3x−90
⇒‌‌3x−y=50
‌

x

(‌ 50 3 )

+‌

y

(−50)

=1.....(i)
and equation of straight line with slope 6 and passing through the point (30,40) is
(y−40)=6(x−30)
⇒‌‌y−40=6x−180
⇒ 6x−y=140
⇒‌

x

(‌ 70 3 )

+‌

y

(−140)

=1......(ii)
∴ The difference between the y -intercepts of the straight lines