KEAM 2013 Math Paper

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Question : 106 of 120

Marks: +1, -0

∫

3x

√1−9x

dx is equal to

(log‌3)sin−1(3x)+C
1
3
sin−1(3x)+C
(
1
log‌3
)sin−1(3x)+C
1
9
sin−1(3x)+C
sin−1(3x)+C

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