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Question : 58 of 120
Marks:
+1,
-0
Solution:
We have,
q1=q2=3µC=3×10−6 r=(2i+3j+k)−(i+j+k) =i+2j r=√(1)2+(2)2=√5 F=‌ =9×109×‌| 3×10−6×3×10−6 |
| (√5)2 |
=‌ F=16.5×10−3N No option is correct.
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