KEAM 2012 Math Paper

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Question : 80 of 120

Marks: +1, -0

The equation of the circle with centre at (1,1) and touching the line 3x+4y+3=0 is

x2+y2−2x−2y+2=0
x2+y2−2x−2y−2=0
x2+y2+2x+2y+2=0
x2+y2−2x−2y−4=0
x2+y2+2x+2y+4=0

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