KEAM 2012 Math Paper

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Question : 40 of 120

Marks: +1, -0

If a,b,c,d are in G.P., then (a+b+c+d)2 is equal to

(a+b)2+(c+d)2+2(b+c)2
(a+b)2+(c+d)2+2(a+c)2
(a+b)2+(c+d)2+2(b+d)2
(a+b)2+(c+d)2+(b+c)2
(a+b)2+(c+d)2+(b−c)2

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