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Question : 4 of 120
Marks:
+1,
-0
Solution:
Let
I=∫‌dx Let
5x=A(1−x)2+B(1−x)+C ⇒‌‌5x=A(1−2x+x2)+B(1−x)+C
On equating the coefficients of
x2,x and constant terms, we get
0=A,5=−2A−B,0=A+B+C ∴‌‌5=−2(0)−B⇒B=−5a
and 0=0−5+C
⇒‌‌C=5 On integrating both sides, we get
=‌+‌ =−‌+‌+C =‌+‌+C
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