KEAM 2012 Math Paper

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Question : 35 of 120

Marks: +1, -0

If y=x+

1

x

,x≠0, then the equation (x2−3x+1)(x2−5x+1)=6x reduces to

y2−8y+7=0
y2+8y+7=0
y2−8y−9=0
y2−8y+9=0
y2−7y−13=0

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