KEAM 2012 Math Paper

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Question : 31 of 120

Marks: +1, -0

Let z1=

2√3+i6√7

6√7+i2√3

and z2=

√11+i3√13

3√13−i√11

. Then |

1

z1

+

1

z2

| is equal to

47
264
|z1−z2|
|z1+z2|
|z1z2|

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