KEAM 2012 Math Paper

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Question : 23 of 120

Marks: +1, -0

If n(A)=1000,n(B)=500 and if n(A∩B)≥1 and n(A∪B)=p, then

500≤p≤1000
1001≤p≤1498
1000≤p≤1498
999≤p≤1499
1000≤p≤1499

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