KEAM 2012 Math Paper

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Question : 21 of 120

Marks: +1, -0

Let ϕ(x)=

b(x−a)

b−a

+

a(x−b)

a−b

, where x∊R and a and b are fixed real numbers with a≠b. Then ϕ(a+b) is equal to

ϕ(ab)
ϕ(−ab)
ϕ(a)+ϕ(b)
ϕ(a−b)
ϕ(0)

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