KEAM 2012 Math Paper

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Question : 108 of 120

Marks: +1, -0

When x≥2, the function f(x)=2|x−2|−|x+1|+xis reduced to

f(x)=−2x+3
f(x)=2x−5
f(x)=5
f(x)=−1
f(x)=−2x−5

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