KEAM 2011 Math Paper

The equation of the line passing through the points (-2,3) and (6,-5) is
(y−3)=‌

−5−3

6+2

(x+2)
⇒‌‌(y−3)=−1(x+2)
⇒‌‌y−3=−x−2
⇒‌‌y=−x+1...(i)Now, the slope of perpendicular bisector of this line is =‌

−1

(−1)

=1
and the perpendicular bisector passing through the mid point of this line is (2,-1)
Then, equation of perpendicular bisector is
(y+1)=1(x−2)
⇒‌‌y+1=x−2
⇒‌‌x−y=3