KEAM 2011 Math Paper

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Question : 62 of 120

Marks: +1, -0

∫√

1−x

1+x

dx is equal to

sin−1x+√1−x2+C
sin−1x−2√1−x2+C
2sin−1x−√1−x2+C
sin−1x−√1−x2+C
−cos−1x−√1−x2+C

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