KEAM 2011 Math Paper

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Question : 60 of 120

Marks: +1, -0

∫

xsin−1x

√1−x2

dx is equal to

x−sin−1x+C
x−√1−x2sin−1x+C
x+sin−1x+C
x+√1−x2sin−1x+C
xsin−1x+√1−x2+C

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