KEAM 2011 Math Paper

© examsiri.com

Question : 30 of 120

Marks: +1, -0

The straight line passing through the point (1,0,−2) and perpendicular to the plane x−2y+5z−7=0 is

x−1
1
=
y
0
=
z−5
−2
x−1
5
=
y
−2
=
z+2
−2
x−5
−2
=
y−1
−5
=
z
1
x−1
−1
=
y
−2
=
z−2
5
x−1
1
=
y
−2
=
z+2
5

Go to Question:

Prev Question

Next Question