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Question : 93 of 119
Marks:
+1,
-0
Solution:
MO configuration of
N2 molecule is
(σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(π2px)2(π2py)2(σ2pz)2
∴ Bond order of
N2==3 MO configuration of
N2+ is
(σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(π2px)2(π2py)2(σ2pz)1
Thus,
N2+ becomes paramagnetic.
∵ Bond order of
N2+==2.5 and bond order
∝ bond energy
∴ In
N2+, the
N−N bond is weakened.
MO configuration of
O2 is
(σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(σ2pz)2(π2px)2(π2py)2(π*2px)1(π*2py)1
∴ Bond order
==2 MO configuration of
O2+ is
(σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(σ2pz)2(π2px)2(π2py)2(π*2px)1
∴ Bond order
==2.5 Hence,
O2 and
O2+ both are paramagnetic, but in
O2+ paramagnetism decreases.
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