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Question : 53 of 120
Marks:
+1,
-0
Solution:
Let
I=∫ I=(ex3+e−x3)(ex+e−x)−∫(3x2ex3−3x2e−x3)(ex+e−x)dx
I=(ex3+e−x3)(ex+e−x) ∴(ex3+e−x3)(ex−e−x)dx =0 Alternate
Let
f(x)=(ex3+e−x3)(ex−e−x) This is an odd function
since,
f(−x)=−f(x) ∴‌‌f(x)dx=0 ∴‌‌(ex3+e−x3)(ex−e−x)dx=0
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