The integral \int_{0}^{1} {2 \sin ^{-1} \frac{x}{2}}/{x} d x equals

Correct Answer is : π∕6∫02xtanxdx

\int_{0}^{\pi \/ 6} \frac{x d x}{\tan x}

\int_{0}^{\pi \/ 6} \frac{2 x}{\tan x} d x

\int_{0}^{\pi \/ 2} \frac{2 x d x}{\tan x}

\int_{0}^{\pi \/ 6} \frac{x d x}{\sin x}

\int_{0}^{\pi \/ 6} \frac{2 x}{\sin x} d x

KEAM 2010 Math Paper

Question : 49 of 120

Marks: +1, -0

The integral

∫

‌

2sin−1

dx equals

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