KEAM 2010 Math Paper

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Question : 47 of 120

Marks: +1, -0

∫‌

dx

√1−e2x

is equal to

log‌e−x+√e−2x−1|+c
logex+√e2x−1|+c
−loge−x+√e−2x−1|+c
−loge−2x+√e−2x−1|+c
log‌e−2x+√e−2x−1|+c

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