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Question : 18 of 120
Marks:
+1,
-0
Solution:
The equation of plane containing the line
‌=‌=‌ and
‌=‌=‌ The required equation is
|| x−1 | (y+1) | 3 |
| x | y−2 | 3+1 |
| 2 | −1 | 3 |
|=0 ⇒‌(x−1)(3y−6+z−1)−(y+1) (3x−2z−2)+z(−x−2y+4)=0
−5x−3y−z+5+2y−3x+2z+2+4z=0
⇒‌−8x−y+5z+7=0 ⇒‌8x+y−5z−7=0
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