KEAM 2010 Math Paper

Comparing given plane 2x−3y+5z−7=0 with the plane lx+my+nz+d=0
⇒‌‌l=2,‌‌m=−3,‌‌z=5
since, the required line is perpendicular to the given plane. Therefore, these are the direction cosine of the line.
∴ Equation of line is
‌

x−3

2

=‌

y−0

−3

=‌

z+4

5

⇒‌‌‌

x−3

2

=−‌

y

3

=‌

z+4

5