The equation of a straight line which passes through the point (a \cos ^{3} \theta, a \sin ^{3} \theta) and perpendicular to x \sec \theta+y cosec \theta=a is

Correct Answer is : xcosθ−ysinθ=acos2θ

\frac{x}{a}+\frac{y}{a}=a \cos \theta

x \cos \theta-y \sin \theta=a \cos 2 \theta

x \cos \theta+y \sin \theta=a \cos 2 \theta

x \cos \theta+y \sin \theta-a \cos 2 \theta=1

x \cos \theta-y \sin \theta+a \cos 2 \theta=-1

KEAM 2010 Math Paper

Question : 114 of 120

Marks: +1, -0

The equation of a straight line which passes through the point (acos3θ,asin3θ) and perpendicular to x‌sec‌θ+ycosecθ=a is

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