While determining the coefficient of viscosity of the given liquid, a spherical steel ball sinks by a distance {\h}=0.9 {\m}. The radius of the ball {\r}=\sqrt{3} \times 10^{-3} {\m}. The time taken by the ball to sink in three trails are tabulated as follows. Trial No. Time taken by the ball to fall by h (in second) 1. 2.75 2. 2.65 3. 2.70 The difference between the densities of the steel ball and the liquid is 7000 {\kg} {\m}^{-3}. If {\g}=10 {\ms}^{-2}, then the coefficient of viscosity of the given liquid at room temperature is

0.14 \times 10^{-3} {\Pa} . { s}

KCET 2025 Physics Paper

Question : 56 of 60

Marks: +1, -0

While determining the coefficient of viscosity of the given liquid, a spherical steel ball sinks by a distance h=0.9m. The radius of the ball r=√3×10−3m. The time taken by the ball to sink in three trails are tabulated as follows.

Trial No.	Time taken by the ball to fall by h (in second)
1.	2.75
2.	2.65
3.	2.70

The difference between the densities of the steel ball and the liquid is 7000‌kg‌m−3. If g=10ms−2, then the coefficient of viscosity of the given liquid at room temperature is

0.14 Pa.s
0.14×10−3‌Pa. s
14 Pa.s
0.28 Pa.s

Validate

Trial No.	Time to sink h (in seconds)
1	2.75
2	2.65
3	2.70

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