KCET 2025 Math Paper

Here's a quick breakdown by cases (last digit must be 0 or 2 ):
Last digit =0
First digit can be 1,2 or 3⇒3 choices
The two middle places are filled by the remaining 2 digits in 2!=2 ways
⇒3×2=6 numbers
Last digit =2
First digit can be 1 or 3 (can't be 0 or 2 ) ⇒2 choices
The two middle places are filled by the remaining 2 digits in 2!=2 ways
⇒2×2=4 numbers
Total =6+4=10.