\CH_3-\C^{|↖{ \CH_3}}_{|↙{ \CH_3}}-\OCH_3+\HI\to\A+\B A and B respectively are

Correct Answer is : A=CH3OH,B=CH3−CH3|C|CH3−I

{\A}= {\CH}_3 {\OH}, {\B}= {\CH}_3- \stackrel{|^{ \CH_3}{\C}}_{|↙{ \CH_3}}- {\OH}

{\A}= {\CH}_3- {\I}, {\B}= {\CH}_3- \C^{|↖{ \CH_3}}_{|↙{ \CH_3}}- {\OH}

{\A}= {\CH}_3 {\OH}, {\B}= {\CH}_3- \C^{|↖{ \CH_3}}_{|↙{ \CH_3}}- {\I}

{\A}={\CH}_3-{\I}, {\B}={\CH}_3-\C^{|↖{ \CH_3}}_{|↙{ \CH_3}}-{\I}

KCET 2025 Chemistry Paper

Question : 29 of 60

Marks: +1, -0

CH3−

‌‌‌‌CH3

−OCH3+HI→A+B
A and B respectively are

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