The real value of ' \alpha ' for which \frac{1-i \sin \alpha}{1+2 i \sin \alpha} is purely real is

( {\n}+1) \frac{\pi}{2}, {\n} \in {\N}

(2 {\n}+1) \frac{\pi}{2}, {\n} \in {\N}

(2 {\n}-1) \frac{\pi}{2}, {\n} \in {\N}

KCET 2024 Math Solved Paper

Question : 58 of 60

Marks: +1, -0

The real value of ' α ' for which ‌

1−isin‌α

1+2isin‌α

is purely real is

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