\int {1}/{ {\x} [6(\log {\x})^2+7 \log {\x}+2.} {\dx}=

Correct Answer is : log|2logx+13logx+2|+C

\frac{1}{2} \log {| \frac{2 \log x+1}{3 \log x+2} |}+ C

\log {| \frac{2 \log x+1}{3 \log x+2} |}+C

\log {| \frac{3 \log x+2}{2 \log x+1} |}+C

\frac{1}{2} \log {| \frac{3 \log x+2}{2 \log x+1} |}+C

KCET 2024 Math Solved Paper

Question : 33 of 60

Marks: +1, -0

‌∫‌

x[6(log‌x)2+7‌log‌x+2.

‌dx=

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