\int \frac{ \sin x}{3+4 \cos ^2 x} \dx=

Correct Answer is : −12√3tan−1(2cosx√3)+c

- {1}/{2 \sqrt{3}} \tan ^{-1} ( {2 \cos x}/{\sqrt{3}}) +c

{1}/{\sqrt{3}} \tan ^{-1} ( {\cos x}/{\sqrt{3}}) +c

{1}/{2 \sqrt{3}} \tan ^{-1} ( {\cos x}/{\sqrt{3}}) +c

- {1}/{\sqrt{3}} \tan ^{-1} ( {2 \cos x}/{\sqrt{3}}) +c

KCET 2024 Math Solved Paper

Question : 31 of 60

Marks: +1, -0

∫‌

sin‌x

3+4cos2x

‌dx=

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