A closed water tank has cross-sectional area A. It has a small hole at a depth of {\h} from the free surface of water. The radius of the hole is r so that r< < \sqrt{\frac{A}{\pi}}. If P_o is the pressure inside the tank above water level, and {\P}_{ {\a}} is the atmospheric pressure, the rate of flow of the water coming out of the hole is [ \rho is the density of water]

Correct Answer is : πr2√2gh+2(Po−Pa)ρ

\pi {\r}^2 \sqrt{ {\gh}+ {2 ( {\P}_{ {\o}}- {\P}_{ {\a}}) }/{\rho}}

\pi {\r}^2 \sqrt{2 {\gh}+ {2 ( {\P}_{ {\o}}- {\P}_{ {\a}}) }/{\rho}}

KCET 2023 Physics Solved Paper

Question : 42 of 60

Marks: +1, -0

A closed water tank has cross-sectional area A. It has a small hole at a depth of h from the free surface of water. The radius of the hole is r so that r<<√‌

. If Po is the pressure inside the tank above water level, and Pa is the atmospheric pressure, the rate of flow of the water coming out of the hole is [ ρ is the density of water]

πr2√2‌gH
πr2√gh+‌
2(Po−Pa)
ρ
πr2√2‌gh
πr2√2‌gh+‌
2(Po−Pa)
ρ

Validate

Go to Question:

Prev Question

Next Question