In the following equation representing \beta^{-}decay, the number of neutrons in the nucleus X is { }_{83}^{210} {\Bi} \to {\X}+ {\e}^{-1}+\overline{ {\v}}

KCET 2023 Physics Solved Paper

Question : 28 of 60

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In the following equation representing β−decay, the number of neutrons in the nucleus X is ‌83210‌Bi→X+e−1+v

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