The horizontal component of Earth's magnetic field at a place is 3 \times 10^{-5} {\T}. If the dip at that place is 45^{\circ}, the resultant magnetic field at that place is

Correct Answer is : 3√2×10−5T

\frac{3}{2} \sqrt{3} \times 10^{-5} {\T}

{3}/{\sqrt{2}} \times 10^{-5} {\T}

KCET 2023 Physics Solved Paper

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The horizontal component of Earth's magnetic field at a place is 3×10−5T. If the dip at that place is 45∘, the resultant magnetic field at that place is

‌
3
2
√3×10−5T
3√2×10−5T
3×10−5T
‌
3
√2
×10−5T

Validate

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