KCET 2022 Math Solved Paper

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Question : 39 of 60

Marks: +1, -0

The solution of the differential equation ‌

dy

dx

=(x+y)2 is

tan−1(x+y)=x+c
cot−1(x+y)=c
tan−1(x+y)=0
cot−1(x+y)=x+c

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