If A=[\table 0 , 1 ; 0 , 0] then (a I+b A)^n is (where I is the identity matrix of order 2 )

Correct Answer is : anI+n⋅an−1b⋅A

a^n I+n \cdot a^{n-1} b \cdot A

KCET 2022 Math Solved Paper

Question : 15 of 60

Marks: +1, -0

If A=[

0	1
0	0

] then (aI+bA)n is (where I is the identity matrix of order 2 )

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a2	2ab
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an	naan−1b
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