KCET 2022 Math Solved Paper

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Question : 10 of 60

Marks: +1, -0

Let the relation R is defined in N by aRb, if 3a+2b=27 then R is

{(1,12)(3,9)(5,6)(7,3)}
{(1,12)(3,9)(5,6)(7,3)(9,0)}
{(0,‌
27
2
)(1,12)(3,9)(5,6)(7,3)}
{(2,1)(9,3)(6,5)(3,7)}

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